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1868 United States presidential election in Nebraska

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1868 United States presidential election in Nebraska

November 3, 1868 1872 →
 
Nominee Ulysses S. Grant Horatio Seymour
Party Republican Democratic
Home state Illinois New York
Running mate Schuyler Colfax Francis Preston Blair, Jr.
Electoral vote 3 0
Popular vote 9,772 5,519
Percentage 63.91% 36.09%


President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Nebraska took place on November 3, 1868, as part of the 1868 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Nebraska participated in its first ever presidential election, having become the 37th state on March 1, 1867. The state was won by Ulysses S. Grant, formerly the 6th Commanding General of the United States Army (R-Illinois), running with Speaker of the House Schuyler Colfax, with 63.91% of the popular vote, against the 18th governor of New York, Horatio Seymour (DNew York), running with former Senator Francis Preston Blair, Jr., with 36.09% of the vote.[1]

Results

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1868 United States presidential election in Nebraska[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 9,772 63.91% 3 100.00%
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 5,519 36.09% 0 0.00%
Total 15,291 100.00% 3 100.00%

See also

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References

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  1. ^ a b c "1868 Presidential Election Results Nebraska".